Base | Representation |
---|---|
bin | 1011110111010001100101… |
… | …0110111100010010000010 |
3 | 1201012000110120222102000122 |
4 | 2331310121112330102002 |
5 | 3202204101211404214 |
6 | 43424235221220242 |
7 | 2514262312054544 |
oct | 275643126742202 |
9 | 51160416872018 |
10 | 13044241122434 |
11 | 417a0390618a5 |
12 | 1568089b61682 |
13 | 7380b35b4082 |
14 | 3314b7991694 |
15 | 17949d67288e |
hex | bdd195bc482 |
13044241122434 has 8 divisors (see below), whose sum is σ = 19567431698688. Its totient is φ = 6521763889540.
The previous prime is 13044241122391. The next prime is 13044241122443. The reversal of 13044241122434 is 43422114244031.
13044241122434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13044241122394 and 13044241122403.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178290122 + ... + 178363269.
It is an arithmetic number, because the mean of its divisors is an integer number (2445928962336).
Almost surely, 213044241122434 is an apocalyptic number.
13044241122434 is a deficient number, since it is larger than the sum of its proper divisors (6523190576254).
13044241122434 is a wasteful number, since it uses less digits than its factorization.
13044241122434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 356671680.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 13044241122434 its reverse (43422114244031), we get a palindrome (56466355366465).
The spelling of 13044241122434 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, one hundred twenty-two thousand, four hundred thirty-four".
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