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13044241122434 = 218287356653391
BaseRepresentation
bin1011110111010001100101…
…0110111100010010000010
31201012000110120222102000122
42331310121112330102002
53202204101211404214
643424235221220242
72514262312054544
oct275643126742202
951160416872018
1013044241122434
11417a0390618a5
121568089b61682
137380b35b4082
143314b7991694
1517949d67288e
hexbdd195bc482

13044241122434 has 8 divisors (see below), whose sum is σ = 19567431698688. Its totient is φ = 6521763889540.

The previous prime is 13044241122391. The next prime is 13044241122443. The reversal of 13044241122434 is 43422114244031.

13044241122434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13044241122394 and 13044241122403.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178290122 + ... + 178363269.

It is an arithmetic number, because the mean of its divisors is an integer number (2445928962336).

Almost surely, 213044241122434 is an apocalyptic number.

13044241122434 is a deficient number, since it is larger than the sum of its proper divisors (6523190576254).

13044241122434 is a wasteful number, since it uses less digits than its factorization.

13044241122434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 356671680.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 13044241122434 its reverse (43422114244031), we get a palindrome (56466355366465).

The spelling of 13044241122434 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, one hundred twenty-two thousand, four hundred thirty-four".

Divisors: 1 2 18287 36574 356653391 713306782 6522120561217 13044241122434