Base | Representation |
---|---|
bin | 11101101010001100100001… |
… | …100001010101100011111011 |
3 | 122002212020012221021001211010 |
4 | 131222030201201111203323 |
5 | 114044134243104242021 |
6 | 1141232405440205003 |
7 | 36322124330544135 |
oct | 3552144141254373 |
9 | 562766187231733 |
10 | 130443014134011 |
11 | 38621631922107 |
12 | 12768891609763 |
13 | 57a2953568717 |
14 | 242d692d74055 |
15 | 10131c73b0976 |
hex | 76a3218558fb |
130443014134011 has 4 divisors (see below), whose sum is σ = 173924018845352. Its totient is φ = 86962009422672.
The previous prime is 130443014133997. The next prime is 130443014134049. The reversal of 130443014134011 is 110431410344031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130443014134011 - 26 = 130443014133947 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 130443014134011.
It is not an unprimeable number, because it can be changed into a prime (130443014134091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21740502355666 + ... + 21740502355671.
It is an arithmetic number, because the mean of its divisors is an integer number (43481004711338).
Almost surely, 2130443014134011 is an apocalyptic number.
130443014134011 is a deficient number, since it is larger than the sum of its proper divisors (43481004711341).
130443014134011 is an equidigital number, since it uses as much as digits as its factorization.
130443014134011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43481004711340.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 130443014134011 its reverse (110431410344031), we get a palindrome (240874424478042).
The spelling of 130443014134011 in words is "one hundred thirty trillion, four hundred forty-three billion, fourteen million, one hundred thirty-four thousand, eleven".
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