13044303140441 has 4 divisors (see below), whose sum is σ = 13347659027472. Its totient is φ = 12740947253412.

The previous prime is 13044303140437. The next prime is 13044303140509. The reversal of 13044303140441 is 14404130344031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044303140441 - 2² = 13044303140437 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044303140398 and 13044303140407.

It is not an unprimeable number, because it can be changed into a prime (13044303140041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151677943451 + ... + 151677943536.

It is an arithmetic number, because the mean of its divisors is an integer number (3336914756868).

Almost surely, 2^{13044303140441} is an apocalyptic number.

It is an amenable number.

13044303140441 is a deficient number, since it is larger than the sum of its proper divisors (303355887031).

13044303140441 is an equidigital number, since it uses as much as digits as its factorization.

13044303140441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 303355887030.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13044303140441 its reverse (14404130344031), we get a palindrome (27448433484472).

The spelling of 13044303140441 in words is "thirteen trillion, forty-four billion, three hundred three million, one hundred forty thousand, four hundred forty-one".