13044313440433 has 8 divisors (see below), whose sum is σ = 14532929481600. Its totient is φ = 11606158960080.

The previous prime is 13044313440409. The next prime is 13044313440437. The reversal of 13044313440433 is 33404431344031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13044313440433 is a prime.

It is a super-2 number, since 2×13044313440433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044313440392 and 13044313440401.

It is not an unprimeable number, because it can be changed into a prime (13044313440437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12615389658 + ... + 12615390691.

It is an arithmetic number, because the mean of its divisors is an integer number (1816616185200).

Almost surely, 2^{13044313440433} is an apocalyptic number.

It is an amenable number.

13044313440433 is a deficient number, since it is larger than the sum of its proper divisors (1488616041167).

13044313440433 is a wasteful number, since it uses less digits than its factorization.

13044313440433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25230780407.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 13044313440433 its reverse (33404431344031), we get a palindrome (46448744784464).

The spelling of 13044313440433 in words is "thirteen trillion, forty-four billion, three hundred thirteen million, four hundred forty thousand, four hundred thirty-three".