13044320340133 has 4 divisors (see below), whose sum is σ = 13044428774208. Its totient is φ = 13044211906060.

The previous prime is 13044320340119. The next prime is 13044320340151. The reversal of 13044320340133 is 33104302344031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044320340133 - 2⁵ = 13044320340101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044320340095 and 13044320340104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044320340113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54036391 + ... + 54277252.

It is an arithmetic number, because the mean of its divisors is an integer number (3261107193552).

Almost surely, 2^{13044320340133} is an apocalyptic number.

It is an amenable number.

13044320340133 is a deficient number, since it is larger than the sum of its proper divisors (108434075).

13044320340133 is a wasteful number, since it uses less digits than its factorization.

13044320340133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108434074.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13044320340133 its reverse (33104302344031), we get a palindrome (46148622684164).

The spelling of 13044320340133 in words is "thirteen trillion, forty-four billion, three hundred twenty million, three hundred forty thousand, one hundred thirty-three".