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1304435545345 = 5260887109069
BaseRepresentation
bin10010111110110110011…
…010101101010100000001
311121200222100121111120101
4102332312122231110001
5132332440444422340
62435125512442401
7163146062122432
oct22766632552401
94550870544511
101304435545345
1146323194a049
121909849a9401
139601402449a
14471c66b7489
1523de8530c9a
hex12fb66ad501

1304435545345 has 4 divisors (see below), whose sum is σ = 1565322654420. Its totient is φ = 1043548436272.

The previous prime is 1304435545337. The next prime is 1304435545397. The reversal of 1304435545345 is 5435455344031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 139046206321 + 1165389339024 = 372889^2 + 1079532^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304435545345 - 23 = 1304435545337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304435545295 and 1304435545304.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130443554530 + ... + 130443554539.

It is an arithmetic number, because the mean of its divisors is an integer number (391330663605).

Almost surely, 21304435545345 is an apocalyptic number.

It is an amenable number.

1304435545345 is a deficient number, since it is larger than the sum of its proper divisors (260887109075).

1304435545345 is an equidigital number, since it uses as much as digits as its factorization.

1304435545345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260887109074.

The product of its (nonzero) digits is 4320000, while the sum is 46.

The spelling of 1304435545345 in words is "one trillion, three hundred four billion, four hundred thirty-five million, five hundred forty-five thousand, three hundred forty-five".

Divisors: 1 5 260887109069 1304435545345