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130444410223 = 281464214983
BaseRepresentation
bin111100101111100010…
…1111011110101101111
3110110200220011121211201
41321133011323311233
54114122232111343
6135531512230331
712265351122661
oct1713705736557
9413626147751
10130444410223
1150359518106
122134569b3a7
13c3bac9516a
146456510531
1535d6d9a94d
hex1e5f17bd6f

130444410223 has 4 divisors (see below), whose sum is σ = 130908625488. Its totient is φ = 129980194960.

The previous prime is 130444410121. The next prime is 130444410241. The reversal of 130444410223 is 322014444031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130444410223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130444410191 and 130444410200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130444410923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232107211 + ... + 232107772.

It is an arithmetic number, because the mean of its divisors is an integer number (32727156372).

Almost surely, 2130444410223 is an apocalyptic number.

130444410223 is a deficient number, since it is larger than the sum of its proper divisors (464215265).

130444410223 is an equidigital number, since it uses as much as digits as its factorization.

130444410223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 464215264.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 130444410223 its reverse (322014444031), we get a palindrome (452458854254).

The spelling of 130444410223 in words is "one hundred thirty billion, four hundred forty-four million, four hundred ten thousand, two hundred twenty-three".

Divisors: 1 281 464214983 130444410223