130444431333 has 4 divisors (see below), whose sum is σ = 173925908448. Its totient is φ = 86962954220.

The previous prime is 130444431329. The next prime is 130444431379. The reversal of 130444431333 is 333134444031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130444431333 - 2² = 130444431329 is a prime.

It is a super-3 number, since 3×130444431333³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130444431294 and 130444431303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130444431833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21740738553 + ... + 21740738558.

It is an arithmetic number, because the mean of its divisors is an integer number (43481477112).

Almost surely, 2^130444431333 is an apocalyptic number.

It is an amenable number.

130444431333 is a deficient number, since it is larger than the sum of its proper divisors (43481477115).

130444431333 is an equidigital number, since it uses as much as digits as its factorization.

130444431333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43481477114.

The product of its (nonzero) digits is 62208, while the sum is 33.

Adding to 130444431333 its reverse (333134444031), we get a palindrome (463578875364).

The spelling of 130444431333 in words is "one hundred thirty billion, four hundred forty-four million, four hundred thirty-one thousand, three hundred thirty-three".