1304455024401 has 4 divisors (see below), whose sum is σ = 1739273365872. Its totient is φ = 869636682932.

The previous prime is 1304455024399. The next prime is 1304455024427. The reversal of 1304455024401 is 1044205544031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304455024401 - 2¹ = 1304455024399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1304455724401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217409170731 + ... + 217409170736.

It is an arithmetic number, because the mean of its divisors is an integer number (434818341468).

Almost surely, 2^{1304455024401} is an apocalyptic number.

It is an amenable number.

1304455024401 is a deficient number, since it is larger than the sum of its proper divisors (434818341471).

1304455024401 is an equidigital number, since it uses as much as digits as its factorization.

1304455024401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434818341470.

The product of its (nonzero) digits is 38400, while the sum is 33.

The spelling of 1304455024401 in words is "one trillion, three hundred four billion, four hundred fifty-five million, twenty-four thousand, four hundred one".