130450415031445 has 8 divisors (see below), whose sum is σ = 156541264366680. Its totient is φ = 104359821139200.

The previous prime is 130450415031437. The next prime is 130450415031451. The reversal of 130450415031445 is 544130514054031.

It can be written as a sum of positive squares in 4 ways, for example, as 10707600429009 + 119742814602436 = 3272247^2 + 10942706^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130450415031445 - 2³ = 130450415031437 is a prime.

It is a super-3 number, since 3×130450415031445³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130450415031398 and 130450415031407.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62735440 + ... + 64781449.

It is an arithmetic number, because the mean of its divisors is an integer number (19567658045835).

Almost surely, 2^{130450415031445} is an apocalyptic number.

It is an amenable number.

130450415031445 is a deficient number, since it is larger than the sum of its proper divisors (26090849335235).

130450415031445 is a wasteful number, since it uses less digits than its factorization.

130450415031445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127721495.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 130450415031445 its reverse (544130514054031), we get a palindrome (674580929085476).

The spelling of 130450415031445 in words is "one hundred thirty trillion, four hundred fifty billion, four hundred fifteen million, thirty-one thousand, four hundred forty-five".