130454113333 has 4 divisors (see below), whose sum is σ = 136126031328. Its totient is φ = 124782195340.

The previous prime is 130454113313. The next prime is 130454113367. The reversal of 130454113333 is 333311454031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130454113333 - 2¹⁷ = 130453982261 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130454113295 and 130454113304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130454113313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2835958963 + ... + 2835959008.

It is an arithmetic number, because the mean of its divisors is an integer number (34031507832).

Almost surely, 2^130454113333 is an apocalyptic number.

It is an amenable number.

130454113333 is a deficient number, since it is larger than the sum of its proper divisors (5671917995).

130454113333 is an equidigital number, since it uses as much as digits as its factorization.

130454113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5671917994.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 130454113333 its reverse (333311454031), we get a palindrome (463765567364).

The spelling of 130454113333 in words is "one hundred thirty billion, four hundred fifty-four million, one hundred thirteen thousand, three hundred thirty-three".