Search a number
-
+
1304982130239 = 32227638757773
BaseRepresentation
bin10010111111010110111…
…111110000111000111111
311121202101110002220002100
4102333112333300320333
5132340100411131424
62435300040000143
7163165450041414
oct22772677607077
94552343086070
101304982130239
114634924343a7
12190ab7a60053
13960a033a3b8
144723911810b
1523e2b4ebdc9
hex12fd6ff0e3f

1304982130239 has 12 divisors (see below), whose sum is σ = 1893278042136. Its totient is φ = 866155538832.

The previous prime is 1304982130217. The next prime is 1304982130259. The reversal of 1304982130239 is 9320312894031.

1304982130239 is a `hidden beast` number, since 1 + 3 + 0 + 498 + 2 + 130 + 23 + 9 = 666.

It is not a de Polignac number, because 1304982130239 - 216 = 1304982064703 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304982130194 and 1304982130203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304982130259) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 319376844 + ... + 319380929.

It is an arithmetic number, because the mean of its divisors is an integer number (157773170178).

Almost surely, 21304982130239 is an apocalyptic number.

1304982130239 is a deficient number, since it is larger than the sum of its proper divisors (588295911897).

1304982130239 is a wasteful number, since it uses less digits than its factorization.

1304982130239 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 638758006 (or 638758003 counting only the distinct ones).

The product of its (nonzero) digits is 279936, while the sum is 45.

The spelling of 1304982130239 in words is "one trillion, three hundred four billion, nine hundred eighty-two million, one hundred thirty thousand, two hundred thirty-nine".

Divisors: 1 3 9 227 681 2043 638757773 1916273319 5748819957 144998014471 434994043413 1304982130239