Base | Representation |
---|---|
bin | 1011110111100110110111… |
… | …0110001110010011010111 |
3 | 1201012120012200222010100112 |
4 | 2331321231312032103113 |
5 | 3202302301103414101 |
6 | 43431022123033235 |
7 | 2514554005112552 |
oct | 275715566162327 |
9 | 51176180863315 |
10 | 13049953576151 |
11 | 41814aa644928 |
12 | 156920306b81b |
13 | 7387b3c226bb |
14 | 33189a50d699 |
15 | 1796d4e0b6bb |
hex | bde6dd8e4d7 |
13049953576151 has 4 divisors (see below), whose sum is σ = 13105961960832. Its totient is φ = 12993945191472.
The previous prime is 13049953576123. The next prime is 13049953576171. The reversal of 13049953576151 is 15167535994031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13049953576151 - 214 = 13049953559767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13049953576171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28004191991 + ... + 28004192456.
It is an arithmetic number, because the mean of its divisors is an integer number (3276490490208).
Almost surely, 213049953576151 is an apocalyptic number.
13049953576151 is a deficient number, since it is larger than the sum of its proper divisors (56008384681).
13049953576151 is an equidigital number, since it uses as much as digits as its factorization.
13049953576151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56008384680.
The product of its (nonzero) digits is 15309000, while the sum is 59.
The spelling of 13049953576151 in words is "thirteen trillion, forty-nine billion, nine hundred fifty-three million, five hundred seventy-six thousand, one hundred fifty-one".
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