Base | Representation |
---|---|
bin | 11101101011000001111000… |
… | …111011100100010110111101 |
3 | 122010001201010100022222020201 |
4 | 131223001320323210112331 |
5 | 114101104121142444010 |
6 | 1141315003413043501 |
7 | 36326223315600256 |
oct | 3553017073442675 |
9 | 563051110288221 |
10 | 130500315203005 |
11 | 38643966883380 |
12 | 12777a03626591 |
13 | 57a8185ac48c7 |
14 | 243236b1d1b2d |
15 | 101492cbe023a |
hex | 76b078ee45bd |
130500315203005 has 16 divisors (see below), whose sum is σ = 171721940923584. Its totient is φ = 94417562004480.
The previous prime is 130500315202981. The next prime is 130500315203023. The reversal of 130500315203005 is 500302513005031.
It is not a de Polignac number, because 130500315203005 - 25 = 130500315202973 is a prime.
It is a super-2 number, since 2×1305003152030052 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6146966079 + ... + 6146987308.
It is an arithmetic number, because the mean of its divisors is an integer number (10732621307724).
Almost surely, 2130500315203005 is an apocalyptic number.
It is an amenable number.
130500315203005 is a deficient number, since it is larger than the sum of its proper divisors (41221625720579).
130500315203005 is a wasteful number, since it uses less digits than its factorization.
130500315203005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12293953596.
The product of its (nonzero) digits is 6750, while the sum is 28.
Adding to 130500315203005 its reverse (500302513005031), we get a palindrome (630802828208036).
The spelling of 130500315203005 in words is "one hundred thirty trillion, five hundred billion, three hundred fifteen million, two hundred three thousand, five".
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