13050043013401 has 4 divisors (see below), whose sum is σ = 13050153649204. Its totient is φ = 13049932377600.

The previous prime is 13050043013383. The next prime is 13050043013411. The reversal of 13050043013401 is 10431034005031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3693026975625 + 9357016037776 = 1921725^2 + 3058924^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13050043013401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13050043013411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55140780 + ... + 55376941.

It is an arithmetic number, because the mean of its divisors is an integer number (3262538412301).

Almost surely, 2^{13050043013401} is an apocalyptic number.

It is an amenable number.

13050043013401 is a deficient number, since it is larger than the sum of its proper divisors (110635803).

13050043013401 is a wasteful number, since it uses less digits than its factorization.

13050043013401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110635802.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13050043013401 its reverse (10431034005031), we get a palindrome (23481077018432).

The spelling of 13050043013401 in words is "thirteen trillion, fifty billion, forty-three million, thirteen thousand, four hundred one".