13050100433 has 6 divisors (see below), whose sum is σ = 13642166034. Its totient is φ = 12482704256.

The previous prime is 13050100423. The next prime is 13050100451. The reversal of 13050100433 is 33400105031.

It is a happy number.

13050100433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 11905428544 + 1144671889 = 109112^2 + 33833^2 .

It is not a de Polignac number, because 13050100433 - 2¹² = 13050096337 is a prime.

It is a super-2 number, since 2×13050100433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13050100423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 12334160 + ... + 12335217.

It is an arithmetic number, because the mean of its divisors is an integer number (2273694339).

Almost surely, 2^13050100433 is an apocalyptic number.

It is an amenable number.

13050100433 is a deficient number, since it is larger than the sum of its proper divisors (592065601).

13050100433 is an equidigital number, since it uses as much as digits as its factorization.

13050100433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24669423 (or 24669400 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 13050100433 its reverse (33400105031), we get a palindrome (46450205464).

The spelling of 13050100433 in words is "thirteen billion, fifty million, one hundred thousand, four hundred thirty-three".