13050343 has 4 divisors (see below), whose sum is σ = 13059648. Its totient is φ = 13041040.

The previous prime is 13050329. The next prime is 13050379. The reversal of 13050343 is 34305031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13050343 - 2¹⁷ = 12919271 is a prime.

It is a super-2 number, since 2×13050343² = 340622904835298, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13050343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13050043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2071 + ... + 5512.

It is an arithmetic number, because the mean of its divisors is an integer number (3264912).

Almost surely, 2^13050343 is an apocalyptic number.

13050343 is a deficient number, since it is larger than the sum of its proper divisors (9305).

13050343 is an equidigital number, since it uses as much as digits as its factorization.

13050343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9304.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 13050343 is about 3612.5258476584. The cubic root of 13050343 is about 235.4365989475.

Adding to 13050343 its reverse (34305031), we get a palindrome (47355374).

The spelling of 13050343 in words is "thirteen million, fifty thousand, three hundred forty-three".