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1305243250141 = 3320093931349
BaseRepresentation
bin10010111111100110100…
…011110110110111011101
311121210001122110011020211
4102333212203312313131
5132341114233001031
62435342004412421
7163205100366055
oct22774643666735
94553048404224
101305243250141
11463606872676
12190b6b3a7111
139611247430c
1447261a8a565
1523e443cabb1
hex12fe68f6ddd

1305243250141 has 4 divisors (see below), whose sum is σ = 1305247513500. Its totient is φ = 1305238986784.

The previous prime is 1305243250111. The next prime is 1305243250169. The reversal of 1305243250141 is 1410523425031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 796797243225 + 508446006916 = 892635^2 + 713054^2 .

It is a cyclic number.

It is not a de Polignac number, because 1305243250141 - 237 = 1167804296669 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1305243250111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1633666 + ... + 2297683.

It is an arithmetic number, because the mean of its divisors is an integer number (326311878375).

Almost surely, 21305243250141 is an apocalyptic number.

It is an amenable number.

1305243250141 is a deficient number, since it is larger than the sum of its proper divisors (4263359).

1305243250141 is an equidigital number, since it uses as much as digits as its factorization.

1305243250141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4263358.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1305243250141 its reverse (1410523425031), we get a palindrome (2715766675172).

The spelling of 1305243250141 in words is "one trillion, three hundred five billion, two hundred forty-three million, two hundred fifty thousand, one hundred forty-one".

Divisors: 1 332009 3931349 1305243250141