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13053050040531 = 34351016680177
BaseRepresentation
bin1011110111110010011001…
…1010010011000011010011
31201012212012111111210221110
42331330212122103003103
53202330121302244111
643432253255024403
72515023514453524
oct275744632230323
951185174453843
1013053050040531
1141828495013a6
12156992806b103
13738b885b0347
14331ab186684b
15179816ba75a6
hexbdf266930d3

13053050040531 has 4 divisors (see below), whose sum is σ = 17404066720712. Its totient is φ = 8702033360352.

The previous prime is 13053050040521. The next prime is 13053050040539. The reversal of 13053050040531 is 13504005035031.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-13053050040531 is a prime.

It is a super-2 number, since 2×130530500405312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13053050040539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2175508340086 + ... + 2175508340091.

It is an arithmetic number, because the mean of its divisors is an integer number (4351016680178).

Almost surely, 213053050040531 is an apocalyptic number.

13053050040531 is a deficient number, since it is larger than the sum of its proper divisors (4351016680181).

13053050040531 is an equidigital number, since it uses as much as digits as its factorization.

13053050040531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4351016680180.

The product of its (nonzero) digits is 13500, while the sum is 30.

Adding to 13053050040531 its reverse (13504005035031), we get a palindrome (26557055075562).

The spelling of 13053050040531 in words is "thirteen trillion, fifty-three billion, fifty million, forty thousand, five hundred thirty-one".

Divisors: 1 3 4351016680177 13053050040531