Base | Representation |
---|---|
bin | 111100110010001010… |
… | …0110101101001100111 |
3 | 110110221000100222001011 |
4 | 1321210110311221213 |
5 | 4114312220444421 |
6 | 135544330043051 |
7 | 12300465263632 |
oct | 1714424655147 |
9 | 413830328034 |
10 | 130532203111 |
11 | 503a4031212 |
12 | 2136ab79487 |
13 | c40322360b |
14 | 6464044c19 |
15 | 35de93d4e1 |
hex | 1e64535a67 |
130532203111 has 4 divisors (see below), whose sum is σ = 133715915424. Its totient is φ = 127348490800.
The previous prime is 130532203093. The next prime is 130532203177. The reversal of 130532203111 is 111302235031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130532203111 is a prime.
It is a super-2 number, since 2×1305322031112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130532203811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1591856095 + ... + 1591856176.
It is an arithmetic number, because the mean of its divisors is an integer number (33428978856).
Almost surely, 2130532203111 is an apocalyptic number.
130532203111 is a deficient number, since it is larger than the sum of its proper divisors (3183712313).
130532203111 is an equidigital number, since it uses as much as digits as its factorization.
130532203111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3183712312.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 130532203111 its reverse (111302235031), we get a palindrome (241834438142).
The spelling of 130532203111 in words is "one hundred thirty billion, five hundred thirty-two million, two hundred three thousand, one hundred eleven".
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