Base | Representation |
---|---|
bin | 10010111111101011010… |
… | …100100000011010110010 |
3 | 11121210021012201120021200 |
4 | 102333223110200122302 |
5 | 132341300204041424 |
6 | 2435353540232030 |
7 | 163210060245600 |
oct | 22775324403262 |
9 | 4553235646250 |
10 | 1305323112114 |
11 | 46364795a0aa |
12 | 190b9209b616 |
13 | 96125b86918 |
14 | 4726c518870 |
15 | 23e4b4038c9 |
hex | 12feb5206b2 |
1305323112114 has 72 divisors (see below), whose sum is σ = 3290160975660. Its totient is φ = 372925207872.
The previous prime is 1305323112097. The next prime is 1305323112127. The reversal of 1305323112114 is 4112113235031.
1305323112114 is a `hidden beast` number, since 1 + 3 + 0 + 532 + 3 + 1 + 12 + 114 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 993875406489 + 311447705625 = 996933^2 + 558075^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 16907352 + ... + 16984380.
Almost surely, 21305323112114 is an apocalyptic number.
1305323112114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1305323112114 is an abundant number, since it is smaller than the sum of its proper divisors (1984837863546).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305323112114 is a wasteful number, since it uses less digits than its factorization.
1305323112114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96264 (or 96254 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 1305323112114 its reverse (4112113235031), we get a palindrome (5417436347145).
The spelling of 1305323112114 in words is "one trillion, three hundred five billion, three hundred twenty-three million, one hundred twelve thousand, one hundred fourteen".
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