Base | Representation |
---|---|
bin | 11000010100000100… |
… | …01011000010010101 |
3 | 1020200200222110212111 |
4 | 30022002023002111 |
5 | 203213112243131 |
6 | 5555132151021 |
7 | 641320511422 |
oct | 141202130225 |
9 | 36620873774 |
10 | 13053243541 |
11 | 5599241088 |
12 | 2643608471 |
13 | 1300424560 |
14 | 8bb868d49 |
15 | 515e6cab1 |
hex | 30a08b095 |
13053243541 has 4 divisors (see below), whose sum is σ = 14057339212. Its totient is φ = 12049147872.
The previous prime is 13053243503. The next prime is 13053243559. The reversal of 13053243541 is 14534235031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14534235031 = 37 ⋅392817163.
It can be written as a sum of positive squares in 2 ways, for example, as 7353748516 + 5699495025 = 85754^2 + 75495^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13053243541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13053243641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502047816 + ... + 502047841.
It is an arithmetic number, because the mean of its divisors is an integer number (3514334803).
Almost surely, 213053243541 is an apocalyptic number.
It is an amenable number.
13053243541 is a deficient number, since it is larger than the sum of its proper divisors (1004095671).
13053243541 is a wasteful number, since it uses less digits than its factorization.
13053243541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1004095670.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13053243541 its reverse (14534235031), we get a palindrome (27587478572).
The spelling of 13053243541 in words is "thirteen billion, fifty-three million, two hundred forty-three thousand, five hundred forty-one".
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