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13053311235351 = 321450367915039
BaseRepresentation
bin1011110111110011010111…
…1110101011010100010111
31201012212212200222212212200
42331330311332223110113
53202331140134012401
643432335225215543
72515033135542462
oct275746576532427
951185780885780
1013053311235351
114182972990992
12156999b6315b3
13738bca7423aa
14331ad84182d9
1517982ea9d686
hexbdf35fab517

13053311235351 has 6 divisors (see below), whose sum is σ = 18854782895520. Its totient is φ = 8702207490228.

The previous prime is 13053311235347. The next prime is 13053311235353. The reversal of 13053311235351 is 15353211335031.

13053311235351 is a `hidden beast` number, since 1 + 3 + 0 + 5 + 3 + 3 + 112 + 3 + 535 + 1 = 666.

It is not a de Polignac number, because 13053311235351 - 22 = 13053311235347 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13053311235353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 725183957511 + ... + 725183957528.

It is an arithmetic number, because the mean of its divisors is an integer number (3142463815920).

Almost surely, 213053311235351 is an apocalyptic number.

13053311235351 is a deficient number, since it is larger than the sum of its proper divisors (5801471660169).

13053311235351 is a wasteful number, since it uses less digits than its factorization.

13053311235351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1450367915045 (or 1450367915042 counting only the distinct ones).

The product of its (nonzero) digits is 60750, while the sum is 36.

The spelling of 13053311235351 in words is "thirteen trillion, fifty-three billion, three hundred eleven million, two hundred thirty-five thousand, three hundred fifty-one".

Divisors: 1 3 9 1450367915039 4351103745117 13053311235351