Search a number
-
+
130534441 = 267148871
BaseRepresentation
bin1111100011111…
…00110000101001
3100002121211120221
413301330300221
5231404100231
620541450041
73143344612
oct761746051
9302554527
10130534441
1167757504
1237870921
1321074b1b
141349cc09
15b6d6d11
hex7c7cc29

130534441 has 4 divisors (see below), whose sum is σ = 130585984. Its totient is φ = 130482900.

The previous prime is 130534433. The next prime is 130534451. The reversal of 130534441 is 144435031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130534441 - 23 = 130534433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130534421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21765 + ... + 27106.

It is an arithmetic number, because the mean of its divisors is an integer number (32646496).

Almost surely, 2130534441 is an apocalyptic number.

It is an amenable number.

130534441 is a deficient number, since it is larger than the sum of its proper divisors (51543).

130534441 is an equidigital number, since it uses as much as digits as its factorization.

130534441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51542.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 130534441 is about 11425.1670009676. The cubic root of 130534441 is about 507.2729501152.

Adding to 130534441 its reverse (144435031), we get a palindrome (274969472).

The spelling of 130534441 in words is "one hundred thirty million, five hundred thirty-four thousand, four hundred forty-one".

Divisors: 1 2671 48871 130534441