Base | Representation |
---|---|
bin | 10010111111101101001… |
… | …010011101001110110111 |
3 | 11121210100100220110110200 |
4 | 102333231022131032313 |
5 | 132341331113011210 |
6 | 2435401003051543 |
7 | 163210614125313 |
oct | 22775512351667 |
9 | 4553310813420 |
10 | 1305354032055 |
11 | 463663358777 |
12 | 190ba0510bb3 |
13 | 9612c3c1548 |
14 | 47272686b43 |
15 | 23e4deb00c0 |
hex | 12fed29d3b7 |
1305354032055 has 12 divisors (see below), whose sum is σ = 2262613655640. Its totient is φ = 696188817072.
The previous prime is 1305354032041. The next prime is 1305354032071. The reversal of 1305354032055 is 5502304535031.
1305354032055 is a `hidden beast` number, since 1 + 3 + 0 + 535 + 40 + 32 + 0 + 55 = 666.
It is not a de Polignac number, because 1305354032055 - 210 = 1305354031031 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14503933645 + ... + 14503933734.
It is an arithmetic number, because the mean of its divisors is an integer number (188551137970).
Almost surely, 21305354032055 is an apocalyptic number.
1305354032055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1305354032055 is a deficient number, since it is larger than the sum of its proper divisors (957259623585).
1305354032055 is a wasteful number, since it uses less digits than its factorization.
1305354032055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29007867390 (or 29007867387 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 36.
Adding to 1305354032055 its reverse (5502304535031), we get a palindrome (6807658567086).
The spelling of 1305354032055 in words is "one trillion, three hundred five billion, three hundred fifty-four million, thirty-two thousand, fifty-five".
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