Base | Representation |
---|---|
bin | 111100110010010010… |
… | …1011010111011111111 |
3 | 110110221022112211001100 |
4 | 1321210211122323333 |
5 | 4114314324101033 |
6 | 135545003144143 |
7 | 12300550240326 |
oct | 1714445327377 |
9 | 413838484040 |
10 | 130536550143 |
11 | 503a65301aa |
12 | 21370515053 |
13 | c4040b611c |
14 | 64648570bd |
15 | 35deeeb513 |
hex | 1e6495aeff |
130536550143 has 12 divisors (see below), whose sum is σ = 188632822248. Its totient is φ = 86987430960.
The previous prime is 130536550139. The next prime is 130536550147. The reversal of 130536550143 is 341055635031.
130536550143 is a `hidden beast` number, since 1 + 3 + 0 + 53 + 65 + 501 + 43 = 666.
It is an interprime number because it is at equal distance from previous prime (130536550139) and next prime (130536550147).
It is not a de Polignac number, because 130536550143 - 22 = 130536550139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130536550098 and 130536550107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130536550147) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3055593 + ... + 3098018.
It is an arithmetic number, because the mean of its divisors is an integer number (15719401854).
Almost surely, 2130536550143 is an apocalyptic number.
130536550143 is a deficient number, since it is larger than the sum of its proper divisors (58096272105).
130536550143 is a wasteful number, since it uses less digits than its factorization.
130536550143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6155974 (or 6155971 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
The spelling of 130536550143 in words is "one hundred thirty billion, five hundred thirty-six million, five hundred fifty thousand, one hundred forty-three".
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