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130536550143 = 3223576153611
BaseRepresentation
bin111100110010010010…
…1011010111011111111
3110110221022112211001100
41321210211122323333
54114314324101033
6135545003144143
712300550240326
oct1714445327377
9413838484040
10130536550143
11503a65301aa
1221370515053
13c4040b611c
1464648570bd
1535deeeb513
hex1e6495aeff

130536550143 has 12 divisors (see below), whose sum is σ = 188632822248. Its totient is φ = 86987430960.

The previous prime is 130536550139. The next prime is 130536550147. The reversal of 130536550143 is 341055635031.

130536550143 is a `hidden beast` number, since 1 + 3 + 0 + 53 + 65 + 501 + 43 = 666.

It is an interprime number because it is at equal distance from previous prime (130536550139) and next prime (130536550147).

It is not a de Polignac number, because 130536550143 - 22 = 130536550139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130536550098 and 130536550107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130536550147) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3055593 + ... + 3098018.

It is an arithmetic number, because the mean of its divisors is an integer number (15719401854).

Almost surely, 2130536550143 is an apocalyptic number.

130536550143 is a deficient number, since it is larger than the sum of its proper divisors (58096272105).

130536550143 is a wasteful number, since it uses less digits than its factorization.

130536550143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6155974 (or 6155971 counting only the distinct ones).

The product of its (nonzero) digits is 81000, while the sum is 36.

The spelling of 130536550143 in words is "one hundred thirty billion, five hundred thirty-six million, five hundred fifty thousand, one hundred forty-three".

Divisors: 1 3 9 2357 7071 21213 6153611 18460833 55382499 14504061127 43512183381 130536550143