Base | Representation |
---|---|
bin | 11000010100001000… |
… | …00111100100101001 |
3 | 1020200201221101121002 |
4 | 30022010013210221 |
5 | 203213230104031 |
6 | 5555151124345 |
7 | 641325034535 |
oct | 141204074451 |
9 | 36621841532 |
10 | 13053753641 |
11 | 559955a355 |
12 | 26438136b5 |
13 | 13005727a6 |
14 | 8bb95cbc5 |
15 | 51601dccb |
hex | 30a107929 |
13053753641 has 4 divisors (see below), whose sum is σ = 13115619984. Its totient is φ = 12991887300.
The previous prime is 13053753619. The next prime is 13053753649. The reversal of 13053753641 is 14635735031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13053753641 - 26 = 13053753577 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13053753595 and 13053753604.
It is not an unprimeable number, because it can be changed into a prime (13053753649) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30932855 + ... + 30933276.
It is an arithmetic number, because the mean of its divisors is an integer number (3278904996).
Almost surely, 213053753641 is an apocalyptic number.
It is an amenable number.
13053753641 is a deficient number, since it is larger than the sum of its proper divisors (61866343).
13053753641 is an equidigital number, since it uses as much as digits as its factorization.
13053753641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61866342.
The product of its (nonzero) digits is 113400, while the sum is 38.
The spelling of 13053753641 in words is "thirteen billion, fifty-three million, seven hundred fifty-three thousand, six hundred forty-one".
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