130543253425645 has 4 divisors (see below), whose sum is σ = 156651904110780. Its totient is φ = 104434602740512.

The previous prime is 130543253425643. The next prime is 130543253425759. The reversal of 130543253425645 is 546524352345031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88681602902281 + 41861650523364 = 9417091^2 + 6470058^2 .

It is a cyclic number.

It is not a de Polignac number, because 130543253425645 - 2¹ = 130543253425643 is a prime.

It is a super-3 number, since 3×130543253425645³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130543253425592 and 130543253425601.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130543253425643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13054325342560 + ... + 13054325342569.

It is an arithmetic number, because the mean of its divisors is an integer number (39162976027695).

Almost surely, 2^{130543253425645} is an apocalyptic number.

It is an amenable number.

130543253425645 is a deficient number, since it is larger than the sum of its proper divisors (26108650685135).

130543253425645 is an equidigital number, since it uses as much as digits as its factorization.

130543253425645 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26108650685134.

The product of its (nonzero) digits is 25920000, while the sum is 52.

The spelling of 130543253425645 in words is "one hundred thirty trillion, five hundred forty-three billion, two hundred fifty-three million, four hundred twenty-five thousand, six hundred forty-five".