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13054353035 = 55209501223
BaseRepresentation
bin11000010100001100…
…11001111010001011
31020200210001211210212
430022012121322023
5203213403244120
65555212031335
7641333112203
oct141206317213
936623054725
1013054353035
115599929719
122643a6254b
131300722569
148bba77403
155160db6c5
hex30a199e8b

13054353035 has 8 divisors (see below), whose sum is σ = 15668262240. Its totient is φ = 10441456704.

The previous prime is 13054353029. The next prime is 13054353043. The reversal of 13054353035 is 53035345031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13054353035 - 210 = 13054352011 is a prime.

It is a super-2 number, since 2×130543530352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13054352992 and 13054353010.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 224567 + ... + 276656.

It is an arithmetic number, because the mean of its divisors is an integer number (1958532780).

Almost surely, 213054353035 is an apocalyptic number.

13054353035 is a deficient number, since it is larger than the sum of its proper divisors (2613909205).

13054353035 is an equidigital number, since it uses as much as digits as its factorization.

13054353035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 506437.

The product of its (nonzero) digits is 40500, while the sum is 32.

Adding to 13054353035 its reverse (53035345031), we get a palindrome (66089698066).

The spelling of 13054353035 in words is "thirteen billion, fifty-four million, three hundred fifty-three thousand, thirty-five".

Divisors: 1 5 5209 26045 501223 2506115 2610870607 13054353035