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130544993 = 592212627
BaseRepresentation
bin1111100011111…
…11010101100001
3100002122101001202
413301333111201
5231404414433
620542010545
73143420435
oct761772541
9302571052
10130544993
1167764427
1237876a55
1321079877
14134a29c5
15b6d9ee8
hex7c7f561

130544993 has 4 divisors (see below), whose sum is σ = 132757680. Its totient is φ = 128332308.

The previous prime is 130544977. The next prime is 130545017. The reversal of 130544993 is 399445031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130544993 - 24 = 130544977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130544963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1106255 + ... + 1106372.

It is an arithmetic number, because the mean of its divisors is an integer number (33189420).

Almost surely, 2130544993 is an apocalyptic number.

It is an amenable number.

130544993 is a deficient number, since it is larger than the sum of its proper divisors (2212687).

130544993 is an equidigital number, since it uses as much as digits as its factorization.

130544993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2212686.

The product of its (nonzero) digits is 58320, while the sum is 38.

The square root of 130544993 is about 11425.6287791964. The cubic root of 130544993 is about 507.2866185384.

Adding to 130544993 its sum of digits (38), we get a palindrome (130545031).

The spelling of 130544993 in words is "one hundred thirty million, five hundred forty-four thousand, nine hundred ninety-three".

Divisors: 1 59 2212627 130544993