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13055035322535 = 355576315607763
BaseRepresentation
bin1011110111111001110010…
…1111100011000010100111
31201020001022212011120212120
42331332130233203002213
53202343203020310120
643433222254321023
72515123642205643
oct275763457430247
951201285146776
1013055035322535
114183678106128
12156a1a0ab9173
137391139a351b
14331c1d3adc23
151798d110e140
hexbdf9cbe30a7

13055035322535 has 16 divisors (see below), whose sum is σ = 20888432440704. Its totient is φ = 6962560197152.

The previous prime is 13055035322489. The next prime is 13055035322543. The reversal of 13055035322535 is 53522353055031.

It is a cyclic number.

It is not a de Polignac number, because 13055035322535 - 28 = 13055035322279 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6967437 + ... + 8640326.

It is an arithmetic number, because the mean of its divisors is an integer number (1305527027544).

Almost surely, 213055035322535 is an apocalyptic number.

13055035322535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13055035322535 is a deficient number, since it is larger than the sum of its proper divisors (7833397118169).

13055035322535 is a wasteful number, since it uses less digits than its factorization.

13055035322535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15663534.

The product of its (nonzero) digits is 1012500, while the sum is 42.

Adding to 13055035322535 its reverse (53522353055031), we get a palindrome (66577388377566).

The spelling of 13055035322535 in words is "thirteen trillion, fifty-five billion, thirty-five million, three hundred twenty-two thousand, five hundred thirty-five".

Divisors: 1 3 5 15 55763 167289 278815 836445 15607763 46823289 78038815 234116445 870335688169 2611007064507 4351678440845 13055035322535