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130553413143 = 3205321197177
BaseRepresentation
bin111100110010110010…
…1101111111000010111
3110110222111021112201220
41321211211233320113
54114333133210033
6135550404421423
712301143462516
oct1714545577027
9413874245656
10130553413143
1150404aa866a
12213760a7873
13c40773b72a
146466ba667d
1535e172cbb3
hex1e6596fe17

130553413143 has 8 divisors (see below), whose sum is σ = 174156014448. Its totient is φ = 86993210304.

The previous prime is 130553413127. The next prime is 130553413147. The reversal of 130553413143 is 341314355031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130553413143 - 24 = 130553413127 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130553413147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10592430 + ... + 10604747.

It is an arithmetic number, because the mean of its divisors is an integer number (21769501806).

Almost surely, 2130553413143 is an apocalyptic number.

130553413143 is a deficient number, since it is larger than the sum of its proper divisors (43602601305).

130553413143 is a wasteful number, since it uses less digits than its factorization.

130553413143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21199233.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 130553413143 its reverse (341314355031), we get a palindrome (471867768174).

The spelling of 130553413143 in words is "one hundred thirty billion, five hundred fifty-three million, four hundred thirteen thousand, one hundred forty-three".

Divisors: 1 3 2053 6159 21197177 63591531 43517804381 130553413143