Base | Representation |
---|---|
bin | 10010111111111100000… |
… | …111111110011110000001 |
3 | 11121210222212012222122021 |
4 | 102333330013332132001 |
5 | 132342334342240001 |
6 | 2435441531041441 |
7 | 163220052506023 |
oct | 22777407763601 |
9 | 4553885188567 |
10 | 1305605040001 |
11 | 46378200a759 |
12 | 1910505a0281 |
13 | 9616c3c7962 |
14 | 47297b46013 |
15 | 23e66042ba1 |
hex | 12ffc1fe781 |
1305605040001 has 4 divisors (see below), whose sum is σ = 1335967947952. Its totient is φ = 1275242132052.
The previous prime is 1305605039989. The next prime is 1305605040023. The reversal of 1305605040001 is 1000405065031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1305605040001 - 25 = 1305605039969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1305605040301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15181453911 + ... + 15181453996.
It is an arithmetic number, because the mean of its divisors is an integer number (333991986988).
Almost surely, 21305605040001 is an apocalyptic number.
It is an amenable number.
1305605040001 is a deficient number, since it is larger than the sum of its proper divisors (30362907951).
1305605040001 is an equidigital number, since it uses as much as digits as its factorization.
1305605040001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30362907950.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 1305605040001 in words is "one trillion, three hundred five billion, six hundred five million, forty thousand, one".
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