Base | Representation |
---|---|
bin | 10010111111111100000… |
… | …111111110100000100001 |
3 | 11121210222212012222212012 |
4 | 102333330013332200201 |
5 | 132342334342241121 |
6 | 2435441531042305 |
7 | 163220052506342 |
oct | 22777407764041 |
9 | 4553885188765 |
10 | 1305605040161 |
11 | 46378200a894 |
12 | 1910505a0395 |
13 | 9616c3c7a56 |
14 | 47297b460c9 |
15 | 23e66042c5b |
hex | 12ffc1fe821 |
1305605040161 has 4 divisors (see below), whose sum is σ = 1305622734000. Its totient is φ = 1305587346324.
The previous prime is 1305605040149. The next prime is 1305605040209. The reversal of 1305605040161 is 1610405065031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1305605040161 - 218 = 1305604778017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1305605040361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8735771 + ... + 8883968.
It is an arithmetic number, because the mean of its divisors is an integer number (326405683500).
Almost surely, 21305605040161 is an apocalyptic number.
It is an amenable number.
1305605040161 is a deficient number, since it is larger than the sum of its proper divisors (17693839).
1305605040161 is an equidigital number, since it uses as much as digits as its factorization.
1305605040161 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17693838.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 1305605040161 in words is "one trillion, three hundred five billion, six hundred five million, forty thousand, one hundred sixty-one".
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