Base | Representation |
---|---|
bin | 1011111000001110010011… |
… | …1010111101100001011001 |
3 | 1201020120112120112020200201 |
4 | 2332003210322331201121 |
5 | 3202440442024211213 |
6 | 43435532501302201 |
7 | 2515410246561430 |
oct | 276034472754131 |
9 | 51216476466621 |
10 | 13060541241433 |
11 | 4185a43052524 |
12 | 156b278a04961 |
13 | 7397b05aa2ba |
14 | 3321c2728117 |
15 | 179b0469c6dd |
hex | be0e4ebd859 |
13060541241433 has 32 divisors (see below), whose sum is σ = 16075848280320. Its totient is φ = 10355318292480.
The previous prime is 13060541241413. The next prime is 13060541241463. The reversal of 13060541241433 is 33414214506031.
It is not a de Polignac number, because 13060541241433 - 229 = 13060004370521 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13060541241392 and 13060541241401.
It is not an unprimeable number, because it can be changed into a prime (13060541241413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31253535 + ... + 31668667.
It is an arithmetic number, because the mean of its divisors is an integer number (502370258760).
Almost surely, 213060541241433 is an apocalyptic number.
It is an amenable number.
13060541241433 is a deficient number, since it is larger than the sum of its proper divisors (3015307038887).
13060541241433 is a wasteful number, since it uses less digits than its factorization.
13060541241433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 419697.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 13060541241433 its reverse (33414214506031), we get a palindrome (46474755747464).
The spelling of 13060541241433 in words is "thirteen trillion, sixty billion, five hundred forty-one million, two hundred forty-one thousand, four hundred thirty-three".
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