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130611464211623 = 2391229444663533
BaseRepresentation
bin11101101100101001011001…
…111011011000110010100111
3122010110100000111210122010112
4131230221121323120302213
5114104414234314232443
61141442024530043235
736340236561562133
oct3554513173306247
9563410014718115
10130611464211623
113868701357168a
121279546311951b
1357b57ba371565
1424378b2c303c3
151017785aeeb18
hex76ca59ed8ca7

130611464211623 has 8 divisors (see below), whose sum is σ = 131264675236800. Its totient is φ = 129959142516448.

The previous prime is 130611464211611. The next prime is 130611464211637. The reversal of 130611464211623 is 326112464116031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130611464211623 - 210 = 130611464210599 is a prime.

It is a super-3 number, since 3×1306114642116233 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130611464211223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 222038036 + ... + 222625497.

It is an arithmetic number, because the mean of its divisors is an integer number (16408084404600).

Almost surely, 2130611464211623 is an apocalyptic number.

130611464211623 is a deficient number, since it is larger than the sum of its proper divisors (653211025177).

130611464211623 is a wasteful number, since it uses less digits than its factorization.

130611464211623 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444665001.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 130611464211623 in words is "one hundred thirty trillion, six hundred eleven billion, four hundred sixty-four million, two hundred eleven thousand, six hundred twenty-three".

Divisors: 1 239 1229 293731 444663533 106274584387 546491482057 130611464211623