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130613350423 = 193701965411
BaseRepresentation
bin111100110100100101…
…0011001000000010111
3110111010200001200020011
41321221022121000113
54114444004203143
6140000345221051
712302502106003
oct1715112310027
9414120050204
10130613350423
1150435916406
1221392191787
13c416c95c8a
146470b29703
1535e6b1be9d
hex1e69299017

130613350423 has 8 divisors (see below), whose sum is σ = 131477529456. Its totient is φ = 129751104000.

The previous prime is 130613350391. The next prime is 130613350447. The reversal of 130613350423 is 324053316031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130613350423 - 25 = 130613350391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130613350463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 347413 + ... + 617998.

It is an arithmetic number, because the mean of its divisors is an integer number (16434691182).

Almost surely, 2130613350423 is an apocalyptic number.

130613350423 is a deficient number, since it is larger than the sum of its proper divisors (864179033).

130613350423 is an equidigital number, since it uses as much as digits as its factorization.

130613350423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 966305.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 130613350423 its reverse (324053316031), we get a palindrome (454666666454).

The spelling of 130613350423 in words is "one hundred thirty billion, six hundred thirteen million, three hundred fifty thousand, four hundred twenty-three".

Divisors: 1 193 701 135293 965411 186324323 676753111 130613350423