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13064433 = 34354811
BaseRepresentation
bin110001110101…
…100011110001
3220120202000220
4301311203301
511321030213
61144003253
7216021504
oct61654361
926522026
1013064433
117413558
124460529
132925645
141a4113b
151230e23
hexc758f1

13064433 has 4 divisors (see below), whose sum is σ = 17419248. Its totient is φ = 8709620.

The previous prime is 13064411. The next prime is 13064453. The reversal of 13064433 is 33446031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13064433 - 212 = 13060337 is a prime.

It is a super-2 number, since 2×130644332 = 341358819222978, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13064453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2177403 + ... + 2177408.

It is an arithmetic number, because the mean of its divisors is an integer number (4354812).

Almost surely, 213064433 is an apocalyptic number.

It is an amenable number.

13064433 is a deficient number, since it is larger than the sum of its proper divisors (4354815).

13064433 is an equidigital number, since it uses as much as digits as its factorization.

13064433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4354814.

The product of its (nonzero) digits is 2592, while the sum is 24.

The square root of 13064433 is about 3614.4754806196. The cubic root of 13064433 is about 235.5212993659.

The spelling of 13064433 in words is "thirteen million, sixty-four thousand, four hundred thirty-three".

Divisors: 1 3 4354811 13064433