Base | Representation |
---|---|
bin | 1011111000011101010111… |
… | …1100101111010101111111 |
3 | 1201020221222101121022112011 |
4 | 2332013111330233111333 |
5 | 3203022232231013303 |
6 | 43441442033352051 |
7 | 2515612411235623 |
oct | 276072574572577 |
9 | 51227871538464 |
10 | 13064585016703 |
11 | 4187728715760 |
12 | 1570007108627 |
13 | 739ca62b7a2c |
14 | 3324877d5183 |
15 | 179c8e6bd16d |
hex | be1d5f2f57f |
13064585016703 has 8 divisors (see below), whose sum is σ = 14253731819856. Its totient is φ = 11875681089600.
The previous prime is 13064585016689. The next prime is 13064585016787. The reversal of 13064585016703 is 30761058546031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13064585016703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13064585316703) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60606526 + ... + 60821707.
It is an arithmetic number, because the mean of its divisors is an integer number (1781716477482).
Almost surely, 213064585016703 is an apocalyptic number.
13064585016703 is a deficient number, since it is larger than the sum of its proper divisors (1189146803153).
13064585016703 is a wasteful number, since it uses less digits than its factorization.
13064585016703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121438025.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 13064585016703 in words is "thirteen trillion, sixty-four billion, five hundred eighty-five million, sixteen thousand, seven hundred three".
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