1307254999680 has 512 divisors, whose sum is σ = 5569767936000. Its totient is φ = 283074269184.

The previous prime is 1307254999643. The next prime is 1307254999717. The reversal of 1307254999680 is 869994527031.

1307254999680 is a `hidden beast` number, since 1 + 3 + 0 + 7 + 2 + 549 + 9 + 9 + 6 + 80 = 666.

It is an interprime number because it is at equal distance from previous prime (1307254999643) and next prime (1307254999717).

It is a Harshad number since it is a multiple of its sum of digits (63).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2013837 + ... + 2582643.

It is an arithmetic number, because the mean of its divisors is an integer number (10878453000).

It is a 1-persistent number, because it is pandigital, but 2⋅1307254999680 = 2614509999360 is not.

Almost surely, 2^{1307254999680} is an apocalyptic number.

1307254999680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1307254999680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2784883968000).

1307254999680 is an abundant number, since it is smaller than the sum of its proper divisors (4262512936320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1307254999680 is a wasteful number, since it uses less digits than its factorization.

1307254999680 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 568861 (or 568843 counting only the distinct ones).

The product of its (nonzero) digits is 29393280, while the sum is 63.

The spelling of 1307254999680 in words is "one trillion, three hundred seven billion, two hundred fifty-four million, nine hundred ninety-nine thousand, six hundred eighty".