130736285419898 has 4 divisors (see below), whose sum is σ = 196104428129850. Its totient is φ = 65368142709948.

The previous prime is 130736285419879. The next prime is 130736285419913. The reversal of 130736285419898 is 898914582637031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112983655408129 + 17752630011769 = 10629377^2 + 4213387^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32684071354973 + ... + 32684071354976.

It is a 2-persistent number, because it is pandigital, and so is 2⋅130736285419898 = 261472570839796, but 3⋅130736285419898 = 392208856259694 is not.

Almost surely, 2^{130736285419898} is an apocalyptic number.

130736285419898 is a deficient number, since it is larger than the sum of its proper divisors (65368142709952).

130736285419898 is an equidigital number, since it uses as much as digits as its factorization.

130736285419898 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65368142709951.

The product of its (nonzero) digits is 627056640, while the sum is 74.

The spelling of 130736285419898 in words is "one hundred thirty trillion, seven hundred thirty-six billion, two hundred eighty-five million, four hundred nineteen thousand, eight hundred ninety-eight".