130801263438244 has 27 divisors (see below), whose sum is σ = 266274326520993. Its totient is φ = 56057615709648.

The previous prime is 130801263438199. The next prime is 130801263438247. The reversal of 130801263438244 is 442834362108031.

The square root of 130801263438244 is 11436838.

It is a perfect power (a square), and thus also a powerful number.

It can be written as a sum of positive squares in only one way, i.e., 45602603820900 + 85198659617344 = 6752970^2 + 9230312^2 .

It is a super-3 number, since 3×130801263438244³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (49).

It is not an unprimeable number, because it can be changed into a prime (130801263438247) by changing a digit.

It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 159707274 + ... + 160524190.

Almost surely, 2^{130801263438244} is an apocalyptic number.

130801263438244 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

130801263438244 is the 11436838-th square number.

It is an amenable number.

130801263438244 is an abundant number, since it is smaller than the sum of its proper divisors (135473063082749).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130801263438244 is an frugal number, since it uses more digits than its factorization.

130801263438244 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1633852 (or 816926 counting only the distinct ones).

The product of its (nonzero) digits is 2654208, while the sum is 49.

130801263438244 divided by its sum of digits (49) gives a square (2669413539556 = 1633834²).

The spelling of 130801263438244 in words is "one hundred thirty trillion, eight hundred one billion, two hundred sixty-three million, four hundred thirty-eight thousand, two hundred forty-four".