Base | Representation |
---|---|
bin | 11101101111011011001101… |
… | …011100001010001111010011 |
3 | 122011010120210210221100001122 |
4 | 131233123031130022033103 |
5 | 114121031233432244020 |
6 | 1142105441213552455 |
7 | 36360105634406156 |
oct | 3557331534121723 |
9 | 564116723840048 |
10 | 130802380743635 |
11 | 3874aa83a11947 |
12 | 128064647a572b |
13 | 57ca7c48376b3 |
14 | 2442c247adc9d |
15 | 101c70b8ab125 |
hex | 76f6cd70a3d3 |
130802380743635 has 8 divisors (see below), whose sum is σ = 156962924321040. Its totient is φ = 104641859642464.
The previous prime is 130802380743631. The next prime is 130802380743641. The reversal of 130802380743635 is 536347083208031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130802380743635 - 22 = 130802380743631 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130802380743631) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12489161 + ... + 20434869.
It is an arithmetic number, because the mean of its divisors is an integer number (19620365540130).
Almost surely, 2130802380743635 is an apocalyptic number.
130802380743635 is a deficient number, since it is larger than the sum of its proper divisors (26160543577405).
130802380743635 is an equidigital number, since it uses as much as digits as its factorization.
130802380743635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11238117.
The product of its (nonzero) digits is 8709120, while the sum is 53.
The spelling of 130802380743635 in words is "one hundred thirty trillion, eight hundred two billion, three hundred eighty million, seven hundred forty-three thousand, six hundred thirty-five".
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