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130802380743635 = 532924037945709
BaseRepresentation
bin11101101111011011001101…
…011100001010001111010011
3122011010120210210221100001122
4131233123031130022033103
5114121031233432244020
61142105441213552455
736360105634406156
oct3557331534121723
9564116723840048
10130802380743635
113874aa83a11947
12128064647a572b
1357ca7c48376b3
142442c247adc9d
15101c70b8ab125
hex76f6cd70a3d3

130802380743635 has 8 divisors (see below), whose sum is σ = 156962924321040. Its totient is φ = 104641859642464.

The previous prime is 130802380743631. The next prime is 130802380743641. The reversal of 130802380743635 is 536347083208031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130802380743635 - 22 = 130802380743631 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130802380743631) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12489161 + ... + 20434869.

It is an arithmetic number, because the mean of its divisors is an integer number (19620365540130).

Almost surely, 2130802380743635 is an apocalyptic number.

130802380743635 is a deficient number, since it is larger than the sum of its proper divisors (26160543577405).

130802380743635 is an equidigital number, since it uses as much as digits as its factorization.

130802380743635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11238117.

The product of its (nonzero) digits is 8709120, while the sum is 53.

The spelling of 130802380743635 in words is "one hundred thirty trillion, eight hundred two billion, three hundred eighty million, seven hundred forty-three thousand, six hundred thirty-five".

Divisors: 1 5 3292403 7945709 16462015 39728545 26160476148727 130802380743635