Base | Representation |
---|---|
bin | 10011000010010000111… |
… | …101001101111110111011 |
3 | 11122001102212201222022121 |
4 | 103002100331031332323 |
5 | 132412443104301042 |
6 | 2440533410102111 |
7 | 163335662520061 |
oct | 23022075157673 |
9 | 4561385658277 |
10 | 1308102025147 |
11 | 464843544645 |
12 | 19162887a937 |
13 | 9647980ca68 |
14 | 47453610031 |
15 | 24060375367 |
hex | 13090f4dfbb |
1308102025147 has 4 divisors (see below), whose sum is σ = 1338523002520. Its totient is φ = 1277681047776.
The previous prime is 1308102025127. The next prime is 1308102025177. The reversal of 1308102025147 is 7415202018031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1308102025147 - 219 = 1308101500859 is a prime.
It is a super-2 number, since 2×13081020251472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1308102025117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15210488622 + ... + 15210488707.
It is an arithmetic number, because the mean of its divisors is an integer number (334630750630).
Almost surely, 21308102025147 is an apocalyptic number.
1308102025147 is a deficient number, since it is larger than the sum of its proper divisors (30420977373).
1308102025147 is an equidigital number, since it uses as much as digits as its factorization.
1308102025147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30420977372.
The product of its (nonzero) digits is 13440, while the sum is 34.
The spelling of 1308102025147 in words is "one trillion, three hundred eight billion, one hundred two million, twenty-five thousand, one hundred forty-seven".
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