1310000113 has 4 divisors (see below), whose sum is σ = 1310295280. Its totient is φ = 1309704948.

The previous prime is 1310000101. The next prime is 1310000149. The reversal of 1310000113 is 3110000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310000113 is a prime.

It is a super-2 number, since 2×1310000113² = 3432200592120025538, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1310000113.

It is not an unprimeable number, because it can be changed into a prime (1310000413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140823 + ... + 149836.

It is an arithmetic number, because the mean of its divisors is an integer number (327573820).

Almost surely, 2^1310000113 is an apocalyptic number.

It is an amenable number.

1310000113 is a deficient number, since it is larger than the sum of its proper divisors (295167).

1310000113 is an equidigital number, since it uses as much as digits as its factorization.

1310000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 295166.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 1310000113 is about 36193.9237027433. The cubic root of 1310000113 is about 1094.1842128248.

Adding to 1310000113 its reverse (3110000131), we get a palindrome (4420000244).

The spelling of 1310000113 in words is "one billion, three hundred ten million, one hundred thirteen", and thus it is an aban number.