Base | Representation |
---|---|
bin | 11101110010010011010001… |
… | …111001110100111100010011 |
3 | 122011211110221220211101210220 |
4 | 131302103101321310330103 |
5 | 114132301022134001303 |
6 | 1142340325201324123 |
7 | 36410303501420412 |
oct | 3562232171647423 |
9 | 564743856741726 |
10 | 131000024125203 |
11 | 38816886500802 |
12 | 12838823036643 |
13 | 581333184999c |
14 | 244c6138c5479 |
15 | 1022927ec8053 |
hex | 7724d1e74f13 |
131000024125203 has 4 divisors (see below), whose sum is σ = 174666698833608. Its totient is φ = 87333349416800.
The previous prime is 131000024125183. The next prime is 131000024125249. The reversal of 131000024125203 is 302521420000131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131000024125203 - 29 = 131000024124691 is a prime.
It is a super-2 number, since 2×1310000241252032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131000024125403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21833337354198 + ... + 21833337354203.
It is an arithmetic number, because the mean of its divisors is an integer number (43666674708402).
Almost surely, 2131000024125203 is an apocalyptic number.
131000024125203 is a deficient number, since it is larger than the sum of its proper divisors (43666674708405).
131000024125203 is an equidigital number, since it uses as much as digits as its factorization.
131000024125203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43666674708404.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 131000024125203 its reverse (302521420000131), we get a palindrome (433521444125334).
The spelling of 131000024125203 in words is "one hundred thirty-one trillion, twenty-four million, one hundred twenty-five thousand, two hundred three".
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