Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010001011011001001101101 |
3 | 122011211110222100110200011021 |
4 | 131302103102101123021231 |
5 | 114132301030224423041 |
6 | 1142340325542054141 |
7 | 36410303605123024 |
oct | 3562232221331155 |
9 | 564743870420137 |
10 | 131000030311021 |
11 | 38816889a46253 |
12 | 1283882511a351 |
13 | 5813332c04431 |
14 | 244c6146558bb |
15 | 10229287eacd1 |
hex | 7724d245b26d |
131000030311021 has 4 divisors (see below), whose sum is σ = 132845101160544. Its totient is φ = 129154959461500.
The previous prime is 131000030311019. The next prime is 131000030311027. The reversal of 131000030311021 is 120113030000131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131000030311021 - 21 = 131000030311019 is a prime.
It is a super-2 number, since 2×1310000303110212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131000030310986 and 131000030311004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000030311027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 922535424655 + ... + 922535424796.
It is an arithmetic number, because the mean of its divisors is an integer number (33211275290136).
Almost surely, 2131000030311021 is an apocalyptic number.
It is an amenable number.
131000030311021 is a deficient number, since it is larger than the sum of its proper divisors (1845070849523).
131000030311021 is an equidigital number, since it uses as much as digits as its factorization.
131000030311021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1845070849522.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131000030311021 its reverse (120113030000131), we get a palindrome (251113060311152).
The spelling of 131000030311021 in words is "one hundred thirty-one trillion, thirty million, three hundred eleven thousand, twenty-one".
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