13100004011301 has 8 divisors (see below), whose sum is σ = 18494123310144. Its totient is φ = 8219610360000.

The previous prime is 13100004011299. The next prime is 13100004011333. The reversal of 13100004011301 is 10311040000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13100004011301 - 2¹ = 13100004011299 is a prime.

It is a super-2 number, since 2×13100004011301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100004012301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128431411825 + ... + 128431411926.

It is an arithmetic number, because the mean of its divisors is an integer number (2311765413768).

Almost surely, 2^{13100004011301} is an apocalyptic number.

It is an amenable number.

13100004011301 is a deficient number, since it is larger than the sum of its proper divisors (5394119298843).

13100004011301 is a wasteful number, since it uses less digits than its factorization.

13100004011301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256862823771.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13100004011301 its reverse (10311040000131), we get a palindrome (23411044011432).

The spelling of 13100004011301 in words is "thirteen trillion, one hundred billion, four million, eleven thousand, three hundred one".