131000041301 has 4 divisors (see below), whose sum is σ = 131001170892. Its totient is φ = 130998911712.

The previous prime is 131000041267. The next prime is 131000041331. The reversal of 131000041301 is 103140000131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 113080203076 + 17919838225 = 336274^2 + 133865^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131000041301 is a prime.

It is a super-2 number, since 2×131000041301² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000041331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367976 + ... + 630401.

It is an arithmetic number, because the mean of its divisors is an integer number (32750292723).

Almost surely, 2^131000041301 is an apocalyptic number.

It is an amenable number.

131000041301 is a deficient number, since it is larger than the sum of its proper divisors (1129591).

131000041301 is an equidigital number, since it uses as much as digits as its factorization.

131000041301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1129590.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131000041301 its reverse (103140000131), we get a palindrome (234140041432).

The spelling of 131000041301 in words is "one hundred thirty-one billion, forty-one thousand, three hundred one".