Base | Representation |
---|---|
bin | 1011111010100001010100… |
… | …0101111100100010110010 |
3 | 1201101100101210220211222211 |
4 | 2332220111011330202302 |
5 | 3204112302024224132 |
6 | 43510020412122334 |
7 | 2521305212612521 |
oct | 276502505744262 |
9 | 51340353824884 |
10 | 13100004133042 |
11 | 41a07538a9032 |
12 | 1576a50a663aa |
13 | 74042c2b4138 |
14 | 3340878404b8 |
15 | 17ab63e3b147 |
hex | bea1517c8b2 |
13100004133042 has 4 divisors (see below), whose sum is σ = 19650006199566. Its totient is φ = 6550002066520.
The previous prime is 13100004133037. The next prime is 13100004133057. The reversal of 13100004133042 is 24033140000131.
13100004133042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10671583694121 + 2428420438921 = 3266739^2 + 1558339^2 .
It is a super-2 number, since 2×131000041330422 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275001033259 + ... + 3275001033262.
Almost surely, 213100004133042 is an apocalyptic number.
13100004133042 is a deficient number, since it is larger than the sum of its proper divisors (6550002066524).
13100004133042 is an equidigital number, since it uses as much as digits as its factorization.
13100004133042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6550002066523.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 13100004133042 its reverse (24033140000131), we get a palindrome (37133144133173).
The spelling of 13100004133042 in words is "thirteen trillion, one hundred billion, four million, one hundred thirty-three thousand, forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •